Fine people, I am sure that there are people out there who could make the calculation, but I won't wait, I will make it for you and show the point behind the topic:

there are four places for integers in this case, each place can only take an integer value from 0 to 9

the probability that the first takes exactly "1" is 1/10, the probability for the second place taking exactly 1 is also 1/10, the same for the third and fourth places

Now what is the probability that each place take "1" at the same time giving "1111"?

since the value of each place is independent on the other, then the probability of "1111" is (1/10)^4 = 1/10000

but we would have the same impression(the same degree of being normal\usual) if the number was "2222" or "3333", i.e all are equivalent, then the probability is nine times the last result, i.e 9/10000(some would ask why not 10/10000, the answer is that "0000" would never appear, so we have 9 equivalent combinations for "1111" instead of 10)

that is still too small probability, how could it happen, oh, have we considered the number of trials out of which it happened once? here is the point, many things appear to be weird just because we miss-estimate the actual number of trials, an issue totally related to human memory and recalling system, I didn't take in consideration how often I look at members posts counter, nor how many active members, a man worshiping a caw, will think that the caw often answers his prayers, because when he recalls he doesn't recall the unanswered prayers,(never heard someone saying:"I once prayed and wasn't answered"), that is it, in the same manner one can show that almost everything that people think to be a "miracle" is just the reflection of normal probability of occurrence.